-16x^2+37x-21=0

Solution for -16x^2+37x-21=0 equation:

-16x^2+37x-21=0

a = -16; b = 37; c = -21;
Δ = b2-4ac
Δ = 372-4·(-16)·(-21)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-5}{2*-16}=\frac{-42}{-32}
=1+5/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+5}{2*-16}=\frac{-32}{-32}
=1
$